Circular Motion Problem

The centripedal force is defined as the mass times the velocity squared divided by the radius of the loop.  The mass of the person is 55kg and her velocity she is traveling by is 65m/s while the radius of the loop is 380m when plugged into the formula the force is 612N.  612N is the force that is pushing the airplane out towards the rim of the loop.

The weight or gravity force is always and can be calculated by multiplying the mass of the women by the gravity force.  The centripetal force calculated before is bigger at 612N, because the centripetal is larger antoher force is therefore normal force.  Since the weight and centripetal forces should equal each other in order to keep the rider from being thrown off the plane.  The Fn is calculated using math skills.  Fa plus Fn must equal 612N. Fo equals 539N.  Using math Fn is found to be 73N.  This 73N force is most likely provided by a protector or harness or any other mechanism keeping the person strapped in.  This is balancing the forces.  The Fn is downward along with the weight force in order to create the state of equilibrium.

The woman is pushed out with 612N when it's greater than the persons weight force pull (539N) because of its greater force exerted outwards.  The person feels lighter than usual.

The Fl represents the normal force on the human.  The Fn or W is the weight force of the human while in the air.  The Fl arrow is straight up to counteract the weight force or Fn arrow.  The two forces need to unbalance or in this case be different because the human is in motion at the time.

Momentum (Collision) Problem

First, grams needs to be converted to kg so the 15g is divided by 1000g which is one kilo.  The 15grams is then converted to 0.015kg.

To find the change in momentum, mass is multiplied by change in velocity.  The velocity is given as 600m/s and the mass was just calculated as 0.015kg.  The change in momentum is found to be 9N.m.  This is the change of the first vehicle.

Next, the other car is 100grams and should be divided by 1000grams which is one kilo to find out the car is 0.1kg in mass.

The change of velocity of both cars is next found with the equation change in momentum equals mass times change in velocity.  The change of momentum was found as 9N.m.  The two masses are added together to find the change of velocity form both cars.  Added together, the mass of 0.115kg is divided by the momentum of both cars.  Finally, the change of velocity in both cars is found as 78.26m/s.

Momentum (Impulse Problem)

The equation of change in momentum equals force multiplied by change in time is implemented.  The problem gives 1320N of net force is acting on the ball.  It also gives 9.0 times 10 to the negative third power seconds as the change in time the ball goes.  By multiplying the Force and change of time together, the momentum is calculated as 11.88N/s.

The to find the change in velocity, the equation change in momentum equals mass multiplied by change in velocity.  The momentum was found to be 11.88N/s, and earlier the mass is given as 140g.  Since the mass is needed in Kg, one will  need to divide 140g by 1000grams because that is 1 Kilo.  The mass will then equal 0.140 kg.  With the mass, one is finally able to divide the momentum of 11.88N/s by the mass, 0.140kg, to find the change in velocity which is 84.86m/s.